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      意法半導體筆試題 簡歷

      時間:2023-04-06 16:45:27 筆試題目 我要投稿
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      意法半導體筆試題 簡歷范文

      A Test for The C Programming Language

      意法半導體筆試題 簡歷范文

        I. History

        1. C was originally designed for and implemented on the (what) operating system on the DEC PDP-11, by (who) .

        2. The most recently approved ANSI/ISO C standard was issued in (when), and single line comments notation “//” is or isn’t a feature of C89.

        II. Syntax and Semantics 1.In a runtime C program, auto variables are stored in , staticvariables are stored in , and function parameters are stored in .

        a. stack b. heap c. neither stack nor heap

        2. The statement “extern int x;” is a , and the keyword extern is used during .

        a. variable declaration b. variable definition c. compilation time d. runtime

        3. There is a complicated declaration: void ( * signal (int, void(*)(int)) ) (int);If a statement “typedef void (*p) (int);” is given,please rewrite this complicated declaration.

        4. The following code is a segment of C program.

        ..........

        void func(int *p)

        {...........}

        ..........

        main()

        {

        int num=0;

        .........

        func(&num);

        ........

        }

        ..........

        Here, the function argument “&num” is passed .

        a. by value b. by reference

        III. Practice

        Create a tree, which has h (h>0) layers, and its each node has w(w>0) sub-nodes.Please complete the following incomplete solution.

        #include

        #include

        struct tree{

        char info;

        p_sub; //link to sub-nodes};

        // allocate memory and initiate

        void dnode ( struct tree* tmp )

        {

        = malloc( sizeof (struct tree) );

        = 0x41;

        = NULL;

        }

        struct tree *dtree (struct tree* subtree, int height, int width)

        {

        int i;

        if ( !subtree ) //if necessary, allocte memory for subtree

        denode(subtree);

        if ( height == 1 )

        return subtree;

        else if ( height == 2 ) {

        struct tree *leaf = NULL;

        for ( i=0; i

        denode ( );

        ;

        leaf = NULL;}

        return subtree;}

        else {

        for ( i=0; i

        }

        return subtree;

        }

        }

        main()

        {

        .........

        struct tree *root = NULL;

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